C32H23FN6O2 structure

C32H23FN6O2

TL;DR: C32H23FN6O2 (CAS 836642-25-2) is a chemical compound with molecular formula C32H23FN6O2 and molecular weight 542.19 g/mol, supplied by Kehong Biological (Henan Kehong Biological Technology Co., Ltd.) with CRO/CDMO custom synthesis services.

N-(1,3-benzodioxol-5-yl)-17-(4-fluorophenyl)-15-methyl-13-phenyl-1,8,11,13,14-pentazatetracyclo[8.7.0.02,7.012,16]heptadeca-2,4,6,8,10,12(16),14-heptaen-9-amine

Also Known As: N-(benzo[d][1,3]dioxol-5-yl)-11-(4-fluorophenyl)-10-methyl-8-phenyl-8,11-dihydropyrazolo[3',4':4,5]pyrimido[1,2-a]quinoxalin-6-amine, N-(1,3-benzodioxol-5-yl)-11-(4-fluorophenyl)-10-methyl-8-phenyl-8,11-dihydropyrazolo[3',4':4,5]pyrimido[1,2-a]quinoxalin-6-amine

CAS: 836642-25-2
Molecular Formula C32H23FN6O2
Molecular Weight 542.19 g/mol
LogP 6.84382
Topological Polar Surface Area 76.27 Ų
Hydrogen Bond Donors 1
Hydrogen Bond Acceptors 7
Rotatable Bonds 3
Exact Mass 542.18665
Heavy Atoms 41
Complexity 1880.7329

Chemical Identifiers

CAS Number 836642-25-2
SMILES CC1=NN(C2=C1C(N3C4=CC=CC=C4N=C(C3=N2)NC5=CC6=C(C=C5)OCO6)C7=CC=C(C=C7)F)C8=CC=CC=C8

Product Overview

C32H23FN6O2 (CAS 836642-25-2), with molecular formula C32H23FN6O2 and molecular weight 542.19 g/mol. IUPAC: N-(1,3-benzodioxol-5-yl)-17-(4-fluorophenyl)-15-methyl-13-phenyl-1,8,11,13,14-pentazatetracyclo[8.7.0.02,7.012,16]heptadeca-2,4,6,8,10,12(16),14-heptaen-9-amine.

🧪
Safety Data Sheet (MSDS / SDS) View the Laboratory Chemical Safety Summary (LCSS) on PubChem — includes GHS classifications, hazard statements, first aid measures, and handling precautions.
View MSDS →

Chemical Property Profile of C32H23FN6O2

XLogP
6.84382
TPSA (Topological Polar Surface Area)
76.27
Hydrogen Bond Donors
1
Hydrogen Bond Acceptors
7
Rotatable Bonds
3
Heavy Atoms
41
Complexity
1880.7329
Exact Mass
542.18665
Monoisotopic Mass
542.18665
Data Source: Chemical property values are referenced from PubChem, the world's largest open chemistry database maintained by the National Center for Biotechnology Information (NCBI), U.S. National Library of Medicine.

Property Insights of C32H23FN6O2

The XLogP value of 6.84382 indicates that C32H23FN6O2 is lipophilic (fat-soluble), which may influence its absorption, distribution, and formulation strategy. The TPSA of 76.27 Ų falls within the moderate polarity range, balancing permeability and solubility for C32H23FN6O2. Following Lipinski's Rule of Five, C32H23FN6O2 has 1 hydrogen bond donor(s) and 7 hydrogen bond acceptor(s), which may warrant consideration for formulation optimization.

Frequently Asked Questions

What is the typical lead time for this product?
Lead time typically ranges from 3-7 business days for in-stock items. For larger quantities or custom orders, please contact us for specific lead times.
Can you provide samples for testing?
Yes, we offer sample quantities for quality testing. Please submit an inquiry with your requirements and we will arrange samples accordingly.
What documentation do you provide with the product?
We provide COA (Certificate of Analysis), MSDS (Material Safety Data Sheet), and technical data sheets with each shipment.
Do you ship internationally?
Yes, we ship to most countries worldwide. Shipping costs and delivery times vary by location. Please contact us for specific shipping information.

Frequently Asked Questions

What is the CAS number of C32H23FN6O2?

The CAS number of C32H23FN6O2 is 836642-25-2.

What is the molecular formula of C32H23FN6O2?

The molecular formula of C32H23FN6O2 is C32H23FN6O2.

What is the molecular weight of C32H23FN6O2?

The molecular weight of C32H23FN6O2 is 542.19 g/mol.

Where can I buy C32H23FN6O2?

You can request a quote for C32H23FN6O2 directly from KEHONG BIO. Contact us or email info@kehongbio.com for pricing and availability.

Does KEHONG BIO offer custom synthesis for C32H23FN6O2?

Yes, KEHONG BIO provides custom synthesis services for C32H23FN6O2 and related compounds. Contact us with your specific requirements including quantity, purity, and timeline.

🤖 科弘生物 AI 助手 ×
您好!我是 科弘生物 AI 助手。可以问我产品搜索、询价、样品或技术问题。如何帮助您?