Urea, N-phenyl-N'-2-quinolinyl- structure

Urea, N-phenyl-N'-2-quinolinyl-

TL;DR: Urea, N-phenyl-N'-2-quinolinyl- (CAS 68435-53-0) is a chemical compound with molecular formula C16H13N3O and molecular weight 263.11 g/mol, supplied by Kehong Biological (Henan Kehong Biological Technology Co., Ltd.) with CRO/CDMO custom synthesis services.

1-phenyl-3-quinolin-2-ylurea

Also Known As: Urea, N-phenyl-N'-2-quinolinyl-, 1-phenyl-3-quinolin-2-ylurea, 1-phenyl-3-(quinolin-2-yl)urea, N-Phenyl-N'-(quinolin-2-yl)urea, RefChem:388162

CAS: 68435-53-0
Molecular Formula C16H13N3O
Molecular Weight 263.11 g/mol
LogP 3.8788
Topological Polar Surface Area 54.02 Ų
Hydrogen Bond Donors 2
Hydrogen Bond Acceptors 2
Rotatable Bonds 2
Exact Mass 263.10587
Heavy Atoms 20
Complexity 740.80786

Chemical Identifiers

CAS Number 68435-53-0
SMILES C1=CC=C(C=C1)NC(=O)NC2=NC3=CC=CC=C3C=C2

Product Overview

Urea, N-phenyl-N'-2-quinolinyl- (CAS 68435-53-0), with molecular formula C16H13N3O and molecular weight 263.11 g/mol. IUPAC: 1-phenyl-3-quinolin-2-ylurea.

🧪
Safety Data Sheet (MSDS / SDS) View the Laboratory Chemical Safety Summary (LCSS) on PubChem — includes GHS classifications, hazard statements, first aid measures, and handling precautions.
View MSDS →

Chemical Property Profile of Urea, N-phenyl-N'-2-quinolinyl-

XLogP
3.8788
TPSA (Topological Polar Surface Area)
54.02
Hydrogen Bond Donors
2
Hydrogen Bond Acceptors
2
Rotatable Bonds
2
Heavy Atoms
20
Complexity
740.80786
Exact Mass
263.10587
Monoisotopic Mass
263.10587
Data Source: Chemical property values are referenced from PubChem, the world's largest open chemistry database maintained by the National Center for Biotechnology Information (NCBI), U.S. National Library of Medicine.

Property Insights of Urea, N-phenyl-N'-2-quinolinyl-

The XLogP value of 3.8788 indicates that Urea, N-phenyl-N'-2-quinolinyl- is lipophilic (fat-soluble), which may influence its absorption, distribution, and formulation strategy. With a topological polar surface area (TPSA) of 54.02 Ų, Urea, N-phenyl-N'-2-quinolinyl- exhibits relatively low polarity, potentially indicating favorable cell membrane permeability. Following Lipinski's Rule of Five, Urea, N-phenyl-N'-2-quinolinyl- has 2 hydrogen bond donor(s) and 2 hydrogen bond acceptor(s), all within the drug-like range, suggesting favorable oral bioavailability potential.

Frequently Asked Questions

What is the typical lead time for this product?
Lead time typically ranges from 3-7 business days for in-stock items. For larger quantities or custom orders, please contact us for specific lead times.
Can you provide samples for testing?
Yes, we offer sample quantities for quality testing. Please submit an inquiry with your requirements and we will arrange samples accordingly.
What documentation do you provide with the product?
We provide COA (Certificate of Analysis), MSDS (Material Safety Data Sheet), and technical data sheets with each shipment.
Do you ship internationally?
Yes, we ship to most countries worldwide. Shipping costs and delivery times vary by location. Please contact us for specific shipping information.

Frequently Asked Questions

What is the CAS number of Urea, N-phenyl-N'-2-quinolinyl-?

The CAS number of Urea, N-phenyl-N'-2-quinolinyl- is 68435-53-0.

What is the molecular formula of Urea, N-phenyl-N'-2-quinolinyl-?

The molecular formula of Urea, N-phenyl-N'-2-quinolinyl- is C16H13N3O.

What is the molecular weight of Urea, N-phenyl-N'-2-quinolinyl-?

The molecular weight of Urea, N-phenyl-N'-2-quinolinyl- is 263.11 g/mol.

Where can I buy Urea, N-phenyl-N'-2-quinolinyl-?

You can request a quote for Urea, N-phenyl-N'-2-quinolinyl- directly from KEHONG BIO. Contact us or email info@kehongbio.com for pricing and availability.

Does KEHONG BIO offer custom synthesis for Urea, N-phenyl-N'-2-quinolinyl-?

Yes, KEHONG BIO provides custom synthesis services for Urea, N-phenyl-N'-2-quinolinyl- and related compounds. Contact us with your specific requirements including quantity, purity, and timeline.

🤖 科弘生物 AI 助手 ×
您好!我是 科弘生物 AI 助手。可以问我产品搜索、询价、样品或技术问题。如何帮助您?