Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-
概要:Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-(CAS 107598-69-6)是一种化学化合物,分子式为C14H22N2O,分子量为234.17 g/mol。河南科弘生物科技有限公司提供CRO/CDMO定制合成服务,支持克级到吨级规格。
3-(3-ethyl-4-propan-2-ylphenyl)-1,1-dimethylurea
又称:Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-, 3-(3-ethyl-4-propan-2-ylphenyl)-1,1-dimethylurea, 3-(3-ethyl-4-propan-2-yl-phenyl)-1,1-dimethyl-urea, N'-[3-Ethyl-4-(propan-2-yl)phenyl]-N,N-dimethylurea
| 分子式 | C14H22N2O |
|---|---|
| 分子量 | 234.17 g/mol |
| LogP | 3.0 |
| 拓扑极性表面积 | 32.3 Ų |
| 氢键供体数 | 1 |
| 氢键受体数 | 1 |
| 可旋转键数 | 3 |
| 精确质量 | 234.17322 |
| 重原子数 | 17 |
| 复杂度 | 251.0 |
化学标识符
| CAS 编号 | 107598-69-6 |
|---|---|
| SMILES | CCC1=C(C=CC(=C1)NC(=O)N(C)C)C(C)C |
| InChIKey | LDOZUNONEZUVKS-UHFFFAOYSA-N |
产品概述
Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-(CAS 107598-69-6),分子式为C14H22N2O,分子量为234.17 g/mol。IUPAC名:3-(3-ethyl-4-propan-2-ylphenyl)-1,1-dimethylurea。
Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-化学性质概览
属性洞察:Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-
Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-的XLogP值为3.0,表明该化合物具有亲脂性(脂溶性好),可能影响其吸收、分布和配方策略。 Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-的拓扑极性表面积(TPSA)为32.3 Ų,极性较低,可能具有较好的细胞膜透过性。 根据Lipinski五规则,Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-有1个氢键供体和1个氢键受体,均在类药范围内,提示具有较好的口服生物利用度潜力。
常见问题
常见问题
Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-的CAS号是多少?
Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-的CAS号为107598-69-6。
Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-的分子式是什么?
Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-的分子式为C14H22N2O。
Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-的分子量是多少?
Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-的分子量为234.17 g/mol。
在哪里可以购买Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-?
您可以直接向科弘生物询价Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-。联系我们或发送邮件至info@kehongbio.com获取报价和库存信息。
科弘生物是否提供Urea, N-(3-ethyl-4-(1-methylethyl)phenyl)-N,N-dimethyl-的定制合成服务?
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